(lg√2+lg3-lg√10)÷lg1.8
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/23 03:32:42
(lg√2+lg3-lg√10)÷lg1.8
(lg√2+lg3-lg√10)÷lg1.8
(lg√2+lg3-lg√10)÷lg1.8
(lg√2+lg3-lg√10)÷lg1.8
=(1/2)(lg2+lg9-lg10)÷lg1.8
=(1/2)lg1.8÷lg1.8
=1/2
(lg√2+lg3-lg√10)/lg1.8
=[lg(√2*3)-1/2]/(lg18-lg10)
=[(lg18)/2-1/2]/(lg18-1)
=1/2
(lg√2+lg3-lg√10)÷lg1.8
=(1/2)(lg2+lg9-lg10)÷lg1.8
=(1/2)lg1.8÷lg1.8
=1/2
(lg√2+lg3-lg√10)÷lg1.8
(lg√2+lg3-lg√10)/lg1.8
(lg根号2+lg3-lg根号10)/lg1.8
{√[(lg3)^2-lg9+1] *(lg√27+lg8-lg√1000)}/(lg0.3*lg1.2)
(1-lg3)(lg8+lg√27-lg√1000)/lg0.3lg1.2
2lg3+lg7+lg(25/7)-lg(9/4)+lg1
高一对数题头晕啦!1. (lg√2+lg3-lg√10)/lg1.8 解:原式={1/2(lg2+lg9_lg10)}/lg1.8=lg1.8/2lg1.8=1/2 (练习册解法)我想问第二个等号后面那步怎么得的,看不懂2. 计算(lg根号27+lg8-lg根号1000)/lg1.2 这题
√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
(lg√2+lg√3-lg√10)/lg1.8
lg√2+lg√5—lg1=?
lg1+lg2+lg3=lg(1+2+3)
计算:(lg√27+lg8+3lg√10)/lg1.2
(lg√27+lg8-3lg√10)/lg1.2我已经知道结果了,
计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1?
计算(lg√27+lg8-lg√1000)/lg1.2 要过程,答案不能是小数.
【lg(根号下27)+lg8-3(lg根号下10)】÷lg1.2=?
高一数学 对数运算1、lg5²+2/3lg8+lg5*lg20+(lg2)²2、(lg根号2+lg3-lg根号10)/lg1.8需要过程!谢谢!
(lg根号2的对数+lg3的对数—lg根号10的对数)除以lg1.8的对数 该如何运算?