2sinθ-cosθ=1 (sinθ+cosθ+1)/(sinθ-cosθ+1)如题已知2sinθ-cosθ=1 求(sinθ+cosθ+1)/(sinθ-cosθ+1)
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2sinθ-cosθ=1 (sinθ+cosθ+1)/(sinθ-cosθ+1)如题已知2sinθ-cosθ=1 求(sinθ+cosθ+1)/(sinθ-cosθ+1)
2sinθ-cosθ=1 (sinθ+cosθ+1)/(sinθ-cosθ+1)
如题
已知2sinθ-cosθ=1 求(sinθ+cosθ+1)/(sinθ-cosθ+1)
2sinθ-cosθ=1 (sinθ+cosθ+1)/(sinθ-cosθ+1)如题已知2sinθ-cosθ=1 求(sinθ+cosθ+1)/(sinθ-cosθ+1)
(sinθ+cosθ+1)/(sinθ-cosθ+1)
=(sinθ+cosθ+2sinθ-cosθ)/(sinθ-cosθ+2sinθ-cosθ)
=3sinθ/(3sinθ-2cosθ)
2sinθ-cosθ=1
(2sinθ -cosθ)^2=1=sin^2θ+cos^2θ
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原式=3sinθ/(3sinθ-3sinθ/2)=2
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2sinθ-cosθ=1 (sinθ+cosθ+1)/(sinθ-cosθ+1)如题已知2sinθ-cosθ=1 求(sinθ+cosθ+1)/(sinθ-cosθ+1)
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