3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
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3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27用加减消元法算的过程
3(X-3)+10(2/3+Y)=13, ①
22(X-3)+5(2/3+Y)=27 ②
①-②×2
3(x-3)+10(2/3+y)-44(x-3)-10(2/3+y)=13-54
-41(x-3)=-41
x-3=1
x=4
3×4+10(2/3+y)=1310(2/3+y)=1
2/3+y=1/10
y=-17/30
∴x=4,y=-17/30
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